Atommag szimmetria

Rohán János

Az atommag felépítése proton és elektron tóruszokból

Az izotópok rugalmas gyűrűs atommag szerkezete, atommag szimmetria, bomlás mechanizmusa

A színek jelentése: 1 , 1 , 1 , 1 , 1

Sor-
szám Rend-
szám Neutron
szám Vegyjel m t_1/2 rendszám = pep hamburger + proton szimmetria
0 -1 0n e 0 stable • -1 = -1p e
1 1 0n H 1 stable • 1 = p p
2 1n n 1 613.9 s • 0 = n n = pe
3 1 1n D 2 stable • 1 = 1D D = pep
4 2 1n He 3 stable • 2 = p+1D He3 = pnp
5 1 2n T 3 12.32 y • 1 = 1T T = pe p ep
6 3 1n Li 4 91 ys • 3 = 2p+1D Li4 = p D p
7 2 2n He 4 stable • 2 = 2D He4 = 2 D
8 1 3n H 4 139 ys • 1 = 1 H4 = pep e pep
9 3 2n Li 5 370 ys • 3 = 1p+2D Li5 = D p D
10 2 3n He 5 0.7 zs • 2 = 1T+1D He5 = D n D
11 1 4n H 5 >910 ys • 1 = 1 H5 = pepe p epep
12 4 2n Be 6 5 zs • 4 = 2p+2D Be6 = 2 He3
13 3 3n Li 6 stable • 3 = 3D Li6 = 3 D
14 2 4n He 6 806.7 ms • 2 = 2T He6 = D 2n D = (T T)
15 1 5n H 6 290 ys • 1 = 1 H6 = pepep e pepep
16 5 2n B 7 0.32 zs • 5 = 3p+2D B7 = He3 p He3
17 4 3n Be 7 53.22 d • 4 = 1p+3D Be7 = D He3 D
18 3 4n Li 7 stable • 3 = 1T+2D Li7 = D T D
19 2 5n He 7 2.9 zs • 2 = 1+1T He7 = D 3n D = (T n T)
20 6 2n C 8 2 zs • 6 = 4p+2D C8 = He3 2p He3
21 5 3n B 8 770 ms • 5 = 2p+3D B8 = He3 D He3
22 4 4n Be 8 67 as • 4 = 4D Be8 = 2 He4 = 4 D
23 3 5n Li 8 840.3 ms • 3 = 2T+1D Li8 = D n D n D = T D T
24 2 6n He 8 119 ms • 2 = 1+1 He8 = T 2n T = (D 4n D)
25 6 3n C 9 126.5 ms • 6 = 3p+3D C9 = 3 He3
26 5 4n B 9 800 zs • 5 = 1p+4D B9 = He4 p He4
27 4 5n Be 9 stable • 4 = 1T+3D Be9 = He4 n He4 = 2D n 2D
28 3 6n Li 9 178.3 ms • 3 = 3T Li9 = T T T
29 2 7n He 9 7 zs • 2 = 1+1 He9 = T 3n T
30 7 3n N 10 200 ys • 7 = 4p+3D N10 = He3 p D p He3
31 6 4n C 10 19.290 s • 6 = 2p+4D C10 = He3 He4 He3
32 5 5n B 10 stable • 5 = 5D B10 = 5 D = He4 D He4
33 4 6n Be 10 1.51x10+6 y • 4 = 2T+2D Be10 = T He4 T
34 3 7n Li 10 2 zs • 3 = 1+2T Li10 = T H4 T
35 2 8n He 10 2.68 zs • 2 = 2 He10 = H5 H5 = T 4n T
36 7 4n N 11 590 ys • 7 = 3p+4D N11 = D p D p D p D = He3 Li5 He3
37 6 5n C 11 20.334 min • 6 = 1p+5D C11 = He4 He3 He4 = (D D p n p D D)
38 5 6n B 11 stable • 5 = 1T+4D B11 = He4 T He4
39 4 7n Be 11 13.81 s • 4 = 3T+1D Be11 = T D n D T = D n D n D n D
40 3 8n Li 11 8.59 ms • 3 = 2+1T Li11 = H4 T H4 = T n T n T
41 8 4n O 12 580 ys • 8 = 4p+4D O12 = 4 He3
42 7 5n N 12 11 ms • 7 = 2p+5D N12 = D D p D p D D
43 6 6n C 12 stable • 6 = 6D C12 = 3 He4 = 6 D = 2 Li6
44 5 7n B 12 20.20 ms • 5 = 2T+3D B12 = D T D T D
45 4 8n Be 12 21.49 ms • 4 = 4T Be12 = T T T T
46 3 9n Li 12 <10 ns • 3 = 2+1 Li12 = H4 H4 H4
47 8 5n O 13 8.58 ms • 8 = 3p+5D O13 = He3 D He3 D He3
48 7 6n N 13 9.965 min • 7 = 1p+6D N13 = D D D p D D D = Li6 p Li6
49 6 7n C 13 stable • 6 = 1T+5D C13 = 3 D n 3 D = Li6 n Li6
50 5 8n B 13 17.33 ms • 5 = 3T+2D B13 = T D T D T
51 4 9n Be 13 0.5 ns • 4 = 1+3T Be13 = T T n T T
52 9 5n F 14 nodata • 9 = 4p+5D F14 = He3 D Li4 D He3
53 8 6n O 14 70.606 s • 8 = 2p+6D O14 = D He3 D D He3 D = Be7 Be7
54 7 7n N 14 stable • 7 = 7D N14 = 7 D = Li6 D Li6
55 6 8n C 14 5700 y • 6 = 2T+4D C14 = T D D D D T = D T D D T D
56 5 9n B 14 12.5 ms • 5 = 4T+1D B14 = T T D T T
57 4 10n Be 14 4.84 ms • 4 = 2+2T Be14 = H4 T T H4
58 9 6n F 15 410 ys • 9 = 3p+6D F15 = He3 D p n p n p D He3
59 8 7n O 15 122.24 s • 8 = 1p+7D O15 = D D D He3 D D D = Be7 n Be7
60 7 8n N 15 stable • 7 = 1T+6D N15 = D D D T D D D
61 6 9n C 15 2.449 s • 6 = 3T+3D C15 = He5 He5 He5
62 5 10n B 15 9.87 ms • 5 = 5T B15 = T T T T T
63 4 11n Be 15 <200 ns • 4 = 3+1T Be15 = H4 T n T H4
64 10 6n Ne 16 3.74 zs • 10 = 4p+6D Ne16 = He3 D He3 He3 D He3 = 2 B8
65 9 7n F 16 11.42 zs • 9 = 2p+7D F16 = He4 He3 D He3 He4
66 8 8n O 16 stable • 8 = 4D+4D O16 = 4 He4 = 8 D
67 7 9n N 16 7.13 s • 7 = 2T+5D N16 = T D D D D D T = T B10 T
68 6 10n C 16 0.747 s • 6 = 4T+2D C16 = T T He4 T T
69 5 11n B 16 <190 pics • 5 = 1+4T B16 = T T H4 T T
70 4 12n Be 16 <200 ns • 4 = 2+2 Be16 = H4 H4 H4 H4
71 10 7n Ne 17 109.2 ms • 10 = 3p+7D Ne17 = He3 He4 He3 He4 He3
72 9 8n F 17 64.49 s • 9 = 1p+8D F17 = D D D D p D D D D
73 8 9n O 17 stable • 8 = 1T+7D O17 = He4 He4 n He4 He4 = 4Dn4D
74 7 10n N 17 4.173 s • 7 = 3T+4D N17 = T He4 T He4 T
75 6 11n C 17 193 ms • 6 = 5T+1D C17 = T D T n T D T
76 5 12n B 17 5.08 ms • 5 = 2+3T B17 = T H4 T H4 T
77 11 7n Na 18 1.3 zs • 11 = 4p+7D Na18 = He3 D He3 D He3 D He3
78 10 8n Ne 18 1672 ms • 10 = 2p+8D Ne18 = He4 He3 He4 He3 He4
79 9 9n F 18 109.77 min • 9 = 9D F18 = 9 D
80 8 10n O 18 stable • 8 = 2T+6D O18 = 2 Be9 = He4nHe4 He4nHe4
81 7 11n N 18 622 ms • 7 = 4T+3D N18 = T D T D T D T = Li8 D Li8
82 6 12n C 18 92 ms • 6 = 6T C18 = 6 T = 2 Li9
83 5 13n B 18 <26 ns • 5 = 3+2T B18 = T n T H4 T n T = He7 H4 He7
84 12 7n Mg 19 nodata • 12 = 5p+7 Mg19 = He3 D He3 He3 He3 D He3 = B8 He3 B8
86 10 9n Ne 19 17.22 s • 10 = 1p+3D + 6D Ne19 = Be7 6D
87 9 10n F 19 stable • 9 = 1T+2D + 6D F19 = Li7 6D vagy Be9 p Be9
88 8 11n O 19 26.464 s • 8 = 3T+5D O19 = Be9nBe9 = He4nHe4 n He4nHe4
89 7 12n N 19 271 ms • 7 = 5T+2D N19 = T T Li7 T T
90 6 13n C 19 46.2 ms • 6 = 1+5T C19 = T T T n T T T = Li9 n Li9 = 3Tn3T
91 5 14n B 19 2.92 ms • 5 = 4+1T B19 = T n T n T n T n T = T n Li11 n T

A szimmetria nem abszolút, mert a szerkezet rugalmas. A magelektronok ragasztó szerepet töltenek be, gluonok nem léteznek.

A magelektronok egymást taszitó hatása nagyobb mint a protonokat összeragasztó hatásuk, mert az elektronok nagyobb felületen fejtenek ki hatást egymásra a protonok kisebb átmérője miatt. Ezért nem is létezhet negativ atommag ahol protonok ragasztanának össze elektronokat (= ez esetben több lenne az elektron mint a ragasztó proton, de ez a szerkezet szétrobban).

J.Lucas, Atommag modell Stabil izotópok, Interactive, Nuclear properties Neutronok nem léteznek
Foton és anyagmodell

Az atommag szerkezete
Problémák a relativitáselmélet körül

Vita 1, Vita 2, Vita 3, Vita 4, Alias rigó fórum: OF OF2 OF3 és Tudomány cikkek archiv SG SG2 Szkept Hypog Csivar Gyakorik

rohan.janos@med.u-szeged.hu

Index Fórum 2022, 2021, 2020, 2019, 2018, 2017, 2016, 2015, 2014, 2013, 2012, 2011, 2010, 2009, 2008, 2007, 2006, 2005

Atommag modellek.

Az oxigénnél kisebb magok hengeres szerkezete proton és electron tóruszok sorozatából áll. A nagyobb atommagok gyűrűs szerkezetűek amelyek `6`, `12`, `18` és 24-es szimmetriával épülnek fel. `6+12 es szimmetria`. `Neutroncsillag`. `Fekete lyuk`.

Sor- szám	Rend- szám	Neutron szám	Vegyjel	m	t_1/2	rendszám = pep hamburger + proton	szimmetria
0	-1	0n	e	0	stable	• -1 = -1p	e
1	1	0n	H	1	stable	• 1 = p	p
2		1n	n	1	613.9 s	• 0 = n	`n` = pe
3	1	1n	D	2	stable	• 1 = 1D	D = pep
4	2	1n	He	3	stable	• 2 = p+1D	He3 = pnp
5	1	2n	T	3	12.32 y	• 1 = 1T	T = pe p ep
6	3	1n	Li	4	91 ys	• 3 = 2p+1D	Li4 = p D p
7	2	2n	He	4	stable	• 2 = 2D	He4 = 2 D
8	1	3n	H	4	139 ys	• 1 = 1	H4 = pep e pep
9	3	2n	Li	5	370 ys	• 3 = 1p+2D	Li5 = D p D
10	2	3n	He	5	0.7 zs	• 2 = 1T+1D	He5 = D n D
11	1	4n	H	5	>910 ys	• 1 = 1	H5 = pepe p epep
12	4	2n	Be	6	5 zs	• 4 = 2p+2D	Be6 = 2 He3
13	3	3n	Li	6	stable	• 3 = 3D	Li6 = 3 D
14	2	4n	He	6	806.7 ms	• 2 = 2T	He6 = D 2n D = (T T)
15	1	5n	H	6	290 ys	• 1 = 1	H6 = pepep e pepep
16	5	2n	B	7	0.32 zs	• 5 = 3p+2D	B7 = He3 p He3
17	4	3n	Be	7	53.22 d	• 4 = 1p+3D	Be7 = D He3 D
18	3	4n	Li	7	stable	• 3 = 1T+2D	Li7 = D T D
19	2	5n	He	7	2.9 zs	• 2 = 1+1T	He7 = D 3n D = (T n T)
20	6	2n	C	8	2 zs	• 6 = 4p+2D	C8 = He3 2p He3
21	5	3n	B	8	770 ms	• 5 = 2p+3D	B8 = He3 D He3
22	4	4n	Be	8	67 as	• 4 = 4D	Be8 = 2 He4 = 4 D
23	3	5n	Li	8	840.3 ms	• 3 = 2T+1D	Li8 = D n D n D = T D T
24	2	6n	He	8	119 ms	• 2 = 1+1	He8 = T 2n T = (D 4n D)
25	6	3n	C	9	126.5 ms	• 6 = 3p+3D	C9 = 3 He3
26	5	4n	B	9	800 zs	• 5 = 1p+4D	B9 = He4 p He4
27	4	5n	Be	9	stable	• 4 = 1T+3D	Be9 = He4 n He4 = 2D n 2D
28	3	6n	Li	9	178.3 ms	• 3 = 3T	Li9 = T T T
29	2	7n	He	9	7 zs	• 2 = 1+1	He9 = T 3n T
30	7	3n	N	10	200 ys	• 7 = 4p+3D	N10 = He3 p D p He3
31	6	4n	C	10	19.290 s	• 6 = 2p+4D	C10 = He3 He4 He3
32	5	5n	B	10	stable	• 5 = 5D	B10 = 5 D = He4 D He4
33	4	6n	Be	10	1.51x10+6 y	• 4 = 2T+2D	Be10 = T He4 T
34	3	7n	Li	10	2 zs	• 3 = 1+2T	Li10 = T H4 T
35	2	8n	He	10	2.68 zs	• 2 = 2	He10 = H5 H5 = T 4n T
36	7	4n	N	11	590 ys	• 7 = 3p+4D	N11 = D p D p D p D = He3 Li5 He3
37	6	5n	C	11	20.334 min	• 6 = 1p+5D	C11 = He4 He3 He4 = (D D p n p D D)
38	5	6n	B	11	stable	• 5 = 1T+4D	B11 = He4 T He4
39	4	7n	Be	11	13.81 s	• 4 = 3T+1D	Be11 = T D n D T = D n D n D n D
40	3	8n	Li	11	8.59 ms	• 3 = 2+1T	Li11 = H4 T H4 = T n T n T
41	8	4n	O	12	580 ys	• 8 = 4p+4D	O12 = 4 He3
42	7	5n	N	12	11 ms	• 7 = 2p+5D	N12 = D D p D p D D
43	6	6n	C	12	stable	• 6 = 6D	C12 = 3 He4 = 6 D = 2 Li6
44	5	7n	B	12	20.20 ms	• 5 = 2T+3D	B12 = D T D T D
45	4	8n	Be	12	21.49 ms	• 4 = 4T	Be12 = T T T T
46	3	9n	Li	12	<10 ns	• 3 = 2+1	Li12 = H4 H4 H4
47	8	5n	O	13	8.58 ms	• 8 = 3p+5D	O13 = He3 D He3 D He3
48	7	6n	N	13	9.965 min	• 7 = 1p+6D	N13 = D D D p D D D = Li6 p Li6
49	6	7n	C	13	stable	• 6 = 1T+5D	C13 = 3 D n 3 D = Li6 n Li6
50	5	8n	B	13	17.33 ms	• 5 = 3T+2D	B13 = T D T D T
51	4	9n	Be	13	0.5 ns	• 4 = 1+3T	Be13 = T T n T T
52	9	5n	F	14	nodata	• 9 = 4p+5D	F14 = He3 D Li4 D He3
53	8	6n	O	14	70.606 s	• 8 = 2p+6D	O14 = D He3 D D He3 D = Be7 Be7
54	7	7n	N	14	stable	• 7 = 7D	N14 = 7 D = Li6 D Li6
55	6	8n	C	14	5700 y	• 6 = 2T+4D	C14 = T D D D D T = D T D D T D
56	5	9n	B	14	12.5 ms	• 5 = 4T+1D	B14 = T T D T T
57	4	10n	Be	14	4.84 ms	• 4 = 2+2T	Be14 = H4 T T H4
58	9	6n	F	15	410 ys	• 9 = 3p+6D	F15 = He3 D p n p n p D He3
59	8	7n	O	15	122.24 s	• 8 = 1p+7D	O15 = D D D He3 D D D = Be7 n Be7
60	7	8n	N	15	stable	• 7 = 1T+6D	N15 = D D D T D D D
61	6	9n	C	15	2.449 s	• 6 = 3T+3D	C15 = He5 He5 He5
62	5	10n	B	15	9.87 ms	• 5 = 5T	B15 = T T T T T
63	4	11n	Be	15	<200 ns	• 4 = 3+1T	Be15 = H4 T n T H4
64	10	6n	Ne	16	3.74 zs	• 10 = 4p+6D	Ne16 = He3 D He3 He3 D He3 = 2 B8
65	9	7n	F	16	11.42 zs	• 9 = 2p+7D	F16 = He4 He3 D He3 He4
66	8	8n	O	16	stable	• 8 = 4D+4D	O16 = 4 He4 = 8 D
67	7	9n	N	16	7.13 s	• 7 = 2T+5D	N16 = T D D D D D T = T B10 T
68	6	10n	C	16	0.747 s	• 6 = 4T+2D	C16 = T T He4 T T
69	5	11n	B	16	<190 pics	• 5 = 1+4T	B16 = T T H4 T T
70	4	12n	Be	16	<200 ns	• 4 = 2+2	Be16 = H4 H4 H4 H4
71	10	7n	Ne	17	109.2 ms	• 10 = 3p+7D	Ne17 = He3 He4 He3 He4 He3
72	9	8n	F	17	64.49 s	• 9 = 1p+8D	F17 = D D D D p D D D D
73	8	9n	O	17	stable	• 8 = 1T+7D	O17 = He4 He4 n He4 He4 = 4Dn4D
74	7	10n	N	17	4.173 s	• 7 = 3T+4D	N17 = T He4 T He4 T
75	6	11n	C	17	193 ms	• 6 = 5T+1D	C17 = T D T n T D T
76	5	12n	B	17	5.08 ms	• 5 = 2+3T	B17 = T H4 T H4 T
77	11	7n	Na	18	1.3 zs	• 11 = 4p+7D	Na18 = He3 D He3 D He3 D He3
78	10	8n	Ne	18	1672 ms	• 10 = 2p+8D	Ne18 = He4 He3 He4 He3 He4
79	9	9n	F	18	109.77 min	• 9 = 9D	F18 = 9 D
80	8	10n	O	18	stable	• 8 = 2T+6D	O18 = 2 Be9 = He4nHe4 He4nHe4
81	7	11n	N	18	622 ms	• 7 = 4T+3D	N18 = T D T D T D T = Li8 D Li8
82	6	12n	C	18	92 ms	• 6 = 6T	C18 = 6 T = 2 Li9
83	5	13n	B	18	<26 ns	• 5 = 3+2T	B18 = T n T H4 T n T = He7 H4 He7
84	12	7n	Mg	19	nodata	• 12 = 5p+7	Mg19 = He3 D He3 He3 He3 D He3 = B8 He3 B8
86	10	9n	Ne	19	17.22 s	• 10 = 1p+3D + 6D	Ne19 = Be7 6D
87	9	10n	F	19	stable	• 9 = 1T+2D + 6D	F19 = Li7 6D vagy Be9 p Be9
88	8	11n	O	19	26.464 s	• 8 = 3T+5D	O19 = Be9nBe9 = He4nHe4 n He4nHe4
89	7	12n	N	19	271 ms	• 7 = 5T+2D	N19 = T T Li7 T T
90	6	13n	C	19	46.2 ms	• 6 = 1+5T	C19 = T T T n T T T = Li9 n Li9 = 3Tn3T
91	5	14n	B	19	2.92 ms	• 5 = 4+1T	B19 = T n T n T n T n T = T n Li11 n T