Atommag szimmetria

Az atommag felépítése proton és elektron tóruszokból

Az izotópok rugalmas gyűrűs atommag szerkezete, atommag szimmetria, bomlás mechanizmusa

A színek jelentése:   1  ,   1  ,   1  ,   1  ,   1  

Sor- szám	Rend- szám	Neutron szám	Vegyjel	m	t1/2	rendszám = pep hamburger + proton	szimmetria
0	-1	0n	e	0	stable	• -1 = -1p	e
1	1	0n	H	1	stable	• 1 = p	p
2		1n	n	1	613.9 s	• 0 = n	n = pe
3	1	1n	D	2	stable	• 1 = 1D	D = pep
4	2	1n	He	3	stable	• 2 = p+1D	He3 = pnp
5	1	2n	T	3	12.32 y	• 1 = 1T	T = pe p ep
6	3	1n	Li	4	91 ys	• 3 = 2p+1D	Li4 = p D p
7	2	2n	He	4	stable	• 2 = 2D	He4 = 2 D
8	1	3n	H	4	139 ys	• 1 = 1	H4 = pep e pep
9	3	2n	Li	5	370 ys	• 3 = 1p+2D	Li5  = D p D
10	2	3n	He	5	0.7 zs	• 2 = 1T+1D	He5 = D n D
11	1	4n	H	5	>910 ys	• 1 = 1	H5 = pepe p epep
12	4	2n	Be	6	5 zs	• 4 = 2p+2D	Be6 = 2 He3
13	3	3n	Li	6	stable	• 3 = 3D	Li6  = 3 D
14	2	4n	He	6	806.7 ms	• 2 = 2T	He6 = D 2n D = (T T)
15	1	5n	H	6	290 ys	• 1 = 1	H6 = pepep e pepep
16	5	2n	B	7	0.32 zs	• 5 = 3p+2D	B7 = He3 p He3
17	4	3n	Be	7	53.22 d	• 4 = 1p+3D	Be7 = D He3 D
18	3	4n	Li	7	stable	• 3 = 1T+2D	Li7  = D T D
19	2	5n	He	7	2.9 zs	• 2 = 1+1T	He7 = D 3n D = (T n T)
20	6	2n	C	8	2 zs	• 6 = 4p+2D	C8  = He3 2p He3
21	5	3n	B	8	770 ms	• 5 = 2p+3D	B8  = He3 D He3
22	4	4n	Be	8	67 as	• 4 = 4D	Be8 = 2 He4 = 4 D
23	3	5n	Li	8	840.3 ms	• 3 = 2T+1D	Li8 = D n D n D = T D T
24	2	6n	He	8	119 ms	• 2 = 1+1	He8 = T 2n T = (D 4n D)
25	6	3n	C	9	126.5 ms	• 6 = 3p+3D	C9  = 3 He3
26	5	4n	B	9	800 zs	• 5 = 1p+4D	B9 = He4 p He4
27	4	5n	Be	9	stable	• 4 = 1T+3D	Be9 = He4 n He4 = 2D n 2D
28	3	6n	Li	9	178.3 ms	• 3 = 3T	Li9  = T T T
29	2	7n	He	9	7 zs	• 2 = 1+1	He9 = T 3n T
30	7	3n	N	10	200 ys	• 7 = 4p+3D	N10 = He3 p D p He3
31	6	4n	C	10	19.290 s	• 6 = 2p+4D	C10 = He3 He4 He3
32	5	5n	B	10	stable	• 5 = 5D	B10 = 5 D = He4 D He4
33	4	6n	Be	10	1.51x10+6 y	• 4 = 2T+2D	Be10 = T He4 T
34	3	7n	Li	10	2 zs	• 3 = 1+2T	Li10 = T H4 T
35	2	8n	He	10	2.68 zs	• 2 = 2	He10 = H5 H5 = T 4n T
36	7	4n	N	11	590 ys	• 7 = 3p+4D	N11 = D p D p D p D = He3 Li5 He3
37	6	5n	C	11	20.334 min	• 6 = 1p+5D	C11 = He4 He3 He4 = (D D p n p D D)
38	5	6n	B	11	stable	• 5 = 1T+4D	B11 = He4 T He4
39	4	7n	Be	11	13.81 s	• 4 = 3T+1D	Be11 = T D n D T = D n D n D n D
40	3	8n	Li	11	8.59 ms	• 3 = 2+1T	Li11 = H4 T H4 = T n T n T
41	8	4n	O	12	580 ys	• 8 = 4p+4D	O12 = 4 He3
42	7	5n	N	12	11 ms	• 7 = 2p+5D	N12 = D D p D p D D
43	6	6n	C	12	stable	• 6 = 6D	C12 = 3 He4 = 6 D = 2 Li6
44	5	7n	B	12	20.20 ms	• 5 = 2T+3D	B12 = D T D T D
45	4	8n	Be	12	21.49 ms	• 4 = 4T	Be12 = T T T T
46	3	9n	Li	12	<10 ns	• 3 = 2+1	Li12 = H4 H4 H4
47	8	5n	O	13	8.58 ms	• 8 = 3p+5D	O13 = He3 D He3 D He3
48	7	6n	N	13	9.965 min	• 7 = 1p+6D	N13 = D D D p D D D = Li6 p Li6
49	6	7n	C	13	stable	• 6 = 1T+5D	C13 = 3 D n 3 D = Li6 n Li6
50	5	8n	B	13	17.33 ms	• 5 = 3T+2D	B13 = T D T D T
51	4	9n	Be	13	0.5 ns	• 4 = 1+3T	Be13 = T T n T T
52	9	5n	F	14	nodata	• 9 = 4p+5D	F14 = He3 D Li4 D He3
53	8	6n	O	14	70.606 s	• 8 = 2p+6D	O14 = D He3 D D He3 D = Be7 Be7
54	7	7n	N	14	stable	• 7 = 7D	N14 = 7 D = Li6 D Li6
55	6	8n	C	14	5700 y	• 6 = 2T+4D	C14 = T D D D D T = D T D D T D
56	5	9n	B	14	12.5 ms	• 5 = 4T+1D	B14 = T T D T T
57	4	10n	Be	14	4.84 ms	• 4 = 2+2T	Be14 = H4 T T H4
58	9	6n	F	15	410 ys	• 9 = 3p+6D	F15 = He3 D p n p n p D He3
59	8	7n	O	15	122.24 s	• 8 = 1p+7D	O15 = D D D He3 D D D = Be7 n Be7
60	7	8n	N	15	stable	• 7 = 1T+6D	N15 = D D D T D D D
61	6	9n	C	15	2.449 s	• 6 = 3T+3D	C15 = He5 He5 He5
62	5	10n	B	15	9.87 ms	• 5 = 5T	B15 = T T T T T
63	4	11n	Be	15	<200 ns	• 4 = 3+1T	Be15 = H4 T n T H4
64	10	6n	Ne	16	3.74 zs	• 10 = 4p+6D	Ne16 = He3 D He3 He3 D He3 = 2 B8
65	9	7n	F	16	11.42 zs	• 9 = 2p+7D	F16 = He4 He3 D He3 He4
66	8	8n	O	16	stable	• 8 = 4D+4D	O16 = 4 He4 = 8 D
67	7	9n	N	16	7.13 s	• 7 = 2T+5D	N16 = T D D D D D T = T B10 T
68	6	10n	C	16	0.747 s	• 6 = 4T+2D	C16 = T T He4 T T
69	5	11n	B	16	<190 pics	• 5 = 1+4T	B16 = T T H4 T T
70	4	12n	Be	16	<200 ns	• 4 = 2+2	Be16 = H4 H4 H4 H4
71	10	7n	Ne	17	109.2 ms	• 10 = 3p+7D	Ne17 = He3 He4 He3 He4 He3
72	9	8n	F	17	64.49 s	• 9 = 1p+8D	F17 = D D D D p D D D D
73	8	9n	O	17	stable	• 8 = 1T+7D	O17 = He4 He4 n He4 He4 = 4Dn4D
74	7	10n	N	17	4.173 s	• 7 = 3T+4D	N17 = T He4 T He4 T
75	6	11n	C	17	193 ms	• 6 = 5T+1D	C17 = T D T n T D T
76	5	12n	B	17	5.08 ms	• 5 = 2+3T	B17 = T H4 T H4 T
77	11	7n	Na	18	1.3 zs	• 11 = 4p+7D	Na18 = He3 D He3 D He3 D He3
78	10	8n	Ne	18	1672 ms	• 10 = 2p+8D	Ne18 = He4 He3 He4 He3 He4
79	9	9n	F	18	109.77 min	• 9 = 9D	F18 = 9 D
80	8	10n	O	18	stable	• 8 = 2T+6D	O18 = 2 Be9 = He4nHe4 He4nHe4
81	7	11n	N	18	622 ms	• 7 = 4T+3D	N18 = T D T D T D T = Li8 D Li8
82	6	12n	C	18	92 ms	• 6 = 6T	C18 = 6 T = 2 Li9
83	5	13n	B	18	<26 ns	• 5 = 3+2T	B18 = T n T H4 T n T = He7 H4 He7
84	12	7n	Mg	19	nodata	• 12 = 5p+7	Mg19 = He3 D He3 He3 He3 D He3 = B8 He3 B8
86	10	9n	Ne	19	17.22 s	• 10 = 1p+3D + 6D	Ne19 = Be7 6D
87	9	10n	F	19	stable	• 9 = 1T+2D + 6D	F19 = Li7 6D vagy Be9 p Be9
88	8	11n	O	19	26.464 s	• 8 = 3T+5D	O19 = Be9nBe9 = He4nHe4 n He4nHe4
89	7	12n	N	19	271 ms	• 7 = 5T+2D	N19 = T T Li7 T T
90	6	13n	C	19	46.2 ms	• 6 = 1+5T	C19 = T T T n T T T = Li9 n Li9 = 3Tn3T
91	5	14n	B	19	2.92 ms	• 5 = 4+1T	B19 = T n T n T n T n T = T n Li11 n T

	rohan.janos@med.u-szeged.hu